Integer x is evenly divisible by 3

2023 Handbook

2023 Test A Math · Question 29 of 57

Question

Integer x is evenly divisible by 3. Which expression below is also evenly divisible by 3?

  • A2x+12x + 1
  • B3x−53x - 5
  • C4x−14x - 1
  • D4x+64x + 6
Show the answer

Correct answer: D

Since integer x is evenly divisible by 3, substitute 3 for x in the answer options to determine which expression is also divisible by 3:

Let x=3x = 3.

Option A:

2x+1=2(3)+1=72x + 1 = 2(3) + 1 = 7

Option B:

3x−5=3(3)−5=43x - 5 = 3(3) - 5 = 4

Option C:

4x−1=4(3)−1=114x - 1 = 4(3) - 1 = 11

Option D:

4x+6=4(3)+6=184x + 6 = 4(3) + 6 = 18

Option D is the only value that is divisible by 3.

Question analysis

This number properties question says an integer x is divisible by 3 and asks which of four linear expressions in x is also divisible by 3, whatever multiple of 3 the integer is. Students can test a multiple of 3 in each expression or think about remainders. Testing a value that is not a multiple of 3 can make a wrong expression look right.

NYS standards
  • 7.EE.2 rewriting expressions to show relationships
  • 6.NS.4 common factors and multiples
Grade level
Grade 7 content, by NYS standard
Compared with grade 7
At grade 7 Grade 7 students rewrite and evaluate linear expressions, but they seldom ask whether one is divisible by 3 for every allowed value. One well-chosen substitution settles it, so the demand is about typical for grade 7.
Estimated difficulty
Straightforward: two steps or one careful reading.
Solution
2 steps
Reading level
Question and choices: about grade 13, 18 words.
Students, last 30 days
Not enough answers yet to show (it takes 10).
Why it is hard, traps and wrong answers (shows the answer)

Why it is hard

The algebra is light; the question turns on choosing a test value that obeys the condition. The habit of trying x = 1 backfires here, because 1 is not a multiple of 3 and it makes two wrong expressions come out divisible. Students who substitute 3, or who see that 4x and 6 are both multiples of 3 whenever x is, settle it quickly, and a second multiple such as 6 confirms it.

  1. Variables instead of numbers moderate Understanding the question

    Nothing pins x down except that it is a multiple of 3, so each expression must be judged for every such x, and any test value has to be a multiple of 3 itself, such as 3 or 6. (Koedinger & Nathan, 2004; Enright, Morley & Sheehan, 2002)

  2. Every choice must be checked minor Choosing the answer

    The four expressions differ only in their coefficients and constants, from 2x + 1 to 4x + 6, so none can be dismissed at a glance; each needs a test or a look at its terms. (Embretson & Wetzel, 1987)

Strategy: Substitute a multiple of 3, such as 3 or 6, for x in every expression and keep the one whose value divides evenly by 3; a second multiple confirms it.

Traps

  • Misreads the question: Misses or misreads a condition or a word in the question: "at least", "each", "remaining", "not".
  • Numbers taken from the question: Combines the numbers in the question without a model of the situation, or is simply a number that appears in the question.

The wrong answers, classified

How the questions are analyzed, and the research behind it

Worked solution, step by step

Formulas used

Adding multiples of 3
3a+3b=3(a+b)3a + 3b = 3(a + b)
a and b are whole numbers, so 3a and 3b are multiples of 3. A multiple of 3 is a number that 3 divides evenly, with nothing left over. Adding two multiples of 3 always gives another multiple of 3, because you can pull the 3 out of both parts.
  1. Sort out the question

    “Evenly divisible by 3” means 3 goes into the number with nothing left over. Such a number is called a multiple of 3, like 3, 6, 9 or 12.

    You know that x is a multiple of 3. You need the expression that is a multiple of 3 every time, whatever multiple of 3 x is.

  2. Test x = 3 in every choice

    Pick a number for x that follows the rule. The easiest one is 3. Put it into each expression.

    ChoiceWorkDivisible by 3?
    A2(3)+1=72(3) + 1 = 7No
    B3(3)−5=43(3) - 5 = 4No
    C4(3)−1=114(3) - 1 = 11No
    D4(3)+6=184(3) + 6 = 18Yes

    Watch out: your test number must be a multiple of 3. With x = 1, choice A gives 3 and looks right. That leads to the wrong choice, A.

  3. See why D always works

    One test could be lucky, so see why D works for every x. Since x is a multiple of 3, 4x is one too. For example, 4 × 3 = 12 and 4 × 6 = 24. The number 6 is also a multiple of 3, since 6 = 3 × 2.

    3a+3b=3(a+b)3a + 3b = 3(a + b)

    So 4x + 6 is a multiple of 3 plus a multiple of 3. That is always a multiple of 3.

  4. Rule out the other choices

    Watch out: choice B starts with 3x, but then it subtracts 5. The 5 is not a multiple of 3, so it spoils the result, and 3(3) − 5 = 4. Choices A and C also add or take away a number that is not a multiple of 3.

    So the answer is D, 4x+64x + 6.

Check your answer

Try two more multiples of 3. With x = 6, choice D gives 4(6)+6=304(6) + 6 = 30, and 30 ÷ 3 = 10. With x = 9, it gives 4(9)+6=424(9) + 6 = 42, and 42 ÷ 3 = 14. Both divide evenly, so D keeps working.

The original DOE question

Question 86 as printed on page 83 of the DOE handbook.
As printed in the DOE’s NYC Guide to the Specialized High Schools Admissions Test (SHSAT) for 2024 Admissions, page 83, question 86. Open page 83 of the handbook (PDF) The handbook letters this question’s choices E–H; here they are A–D (E = A, F = B, G = C, H = D).