In the equation 14/21 = p/7

2018 Handbook

2018 Test B Math · Question 51 of 57

Also in 2026 Practice Test B Math, question 44; 2025 Practice Test B Math, question 51.

Question

1421=p7\frac{14}{21}=\frac{p}{7}

In the equation above, what is the value of pp?

  • A23\frac{2}{3}
  • B33
  • C143\frac{14}{3}
  • D1414
Show the answer

Correct answer: C

1421=p7\frac{14}{21}=\frac{p}{7}

21p=7(14)21p=7(14)

21p=9821p=98

p=9821=143p=\frac{98}{21}=\frac{14}{3}

Question analysis

Students solve a proportion that sets 14/21 equal to a fraction with an unknown numerator p over 7. It tests solving a proportion, either by cross-multiplying or by dividing numerator and denominator by the same factor. It is quick, and the main risk is losing track of what p stands for.

NYS standards
Grade level
Grade 6 content, by NYS standard
Compared with grade 7
Below grade 7 Solving a one-step proportion is grade 6 and 7 ratio work. This one is purely numerical with one or two steps, shorter than the multistep ratio word problems typical of grade 7.
Estimated difficulty
Straightforward: two steps or one careful reading.
Solution
2 steps
Reading level
Question and choices: about grade 10, 15 words.
Students, last 30 days
Not enough answers yet to show (it takes 10).
Why it is hard, traps and wrong answers (shows the answer)

Why it is hard

The method is standard, but the result is not a whole number, and that surprises students who expect the numbers in a proportion to scale evenly. Two intermediate values, the ratio 2/3 and the scale factor 3, appear among the choices. Students who finish the computation and trust a fractional answer get it right.

  1. An answer in an unexpected form moderate Choosing the answer

    The answer is the improper fraction 14/3, not a whole number, so students who expect a tidy proportion distrust their result or reach for the factor 3. (Enright, Morley & Sheehan, 2002)

  2. Error-prone arithmetic minor Working it out

    Cross-multiplying gives 21p = 98, and 98/21 must be reduced by 7; simplifying 14/21 to 2/3 first and multiplying by 7 is quicker. (Brown & Burton, 1978; Junker & Sijtsma, 2001)

Strategy: Cross-multiply to form an equation in p, divide both sides by p's coefficient, and simplify the fraction you get.

Traps

The wrong answers, classified

How the questions are analyzed, and the research behind it

Worked solution, step by step

Formulas used

Cross multiplication
ab=cd means a×d=b×c\frac{a}{b} = \frac{c}{d} \text{ means } a \times d = b \times c
a and c are the top numbers. b and d are the bottom numbers. When two fractions are equal, the top of each times the bottom of the other gives the same answer. It works because you multiply both sides by b and by d.
  1. Sort out the question

    Two fractions are equal: 1421\frac{14}{21} and p7\frac{p}{7}. An equation like this, with two equal fractions, is called a proportion. You need the value of pp.

  2. Cross multiply

    Use cross multiplication. This gets rid of the fractions. Multiply 21 by pp, and multiply 14 by 7.

    21×p=14×7=9821 \times p = 14 \times 7 = 98

  3. Divide to find p

    Divide both sides by 21 to get pp alone.

    p=9821p = \frac{98}{21}

    Both 98 and 21 can be divided by 7.

    98÷721÷7=143\frac{98 \div 7}{21 \div 7} = \frac{14}{3}

  4. Make sense of the fraction

    The answer is 143\frac{14}{3}, which is 4234\frac{2}{3}. It is not a whole number, and that is fine.

    Watch out: 23\frac{2}{3} is the value of 1421\frac{14}{21}, not pp. That is choice A. The 3 is what 21 was divided by to get 7. That gives choice B.

  5. Give the answer

    The top number over 7 must be 143\frac{14}{3} to keep the two fractions equal. So the answer is C, 143\frac{14}{3}.

Check your answer

Think about the bottoms. 7 is one third of 21. So pp must be one third of 14, which is 143\frac{14}{3}. Check it: 143÷7=1421\frac{14}{3} \div 7 = \frac{14}{21}. Both ways agree.

The original DOE question

Question 108 as printed on page 163 of the DOE handbook.
As printed in the DOE’s Specialized High Schools Student Handbook 2018–2019, page 163, question 108. Open page 163 of the handbook (PDF) The handbook letters this question’s choices E–H; here they are A–D (E = A, F = B, G = C, H = D).