Lemont answered 6 out of 40 questions

2019 Handbook

2019 Test A Math · Question 24 of 57

Question

Lemont answered 6 out of 40 questions on a test incorrectly. What percentage of the questions did he answer correctly?

  • A85%
  • B67%
  • C34%
  • D15%
Show the answer

Correct answer: A

If Lemont answered 6 out of 40 questions incorrectly, then he answered 34 questions correctly.

3440=0.85=85%\frac{34}{40} = 0.85 = 85\%

Question analysis

Lemont got 6 of the 40 questions on a test wrong, and students find the percentage of questions he answered correctly. It tests writing part of a whole as a percent. The stem gives the number of incorrect answers, so students must switch to the correct ones before or after turning the fraction into a percent.

NYS standards
Grade level
Grade 6 content, by NYS standard
Compared with grade 7
Below grade 7 Writing a test score as a percent is grade 6 work, and a test of 40 questions makes the division short. Grade 7 percent problems usually add a second change or a reverse step, which this lacks.
Estimated difficulty
Routine: one familiar step, little to misread.
What makes it hard
Solution
2 steps
Reading level
Question and choices: about grade 8, 18 words.
Students, last 30 days
Not enough answers yet to show (it takes 10).
Why it is hard, traps and wrong answers (shows the answer)

Why it is hard

The arithmetic is light, 34 out of 40, so the only real demand is keeping track of which group the question asks about. The stem's one count is of wrong answers, and the percent those make is a listed choice, waiting for anyone who skims the final word. Writing 34 correct before dividing, then checking that the answer is well above half, settles it.

  1. Turning words into math minor Understanding the question

    The stem counts the questions Lemont answered incorrectly, 6, but asks for the percentage he answered correctly, so the 6 must become 34 right, or 15% must come off 100%. (Hegarty, Mayer & Monk, 1995; Koedinger & Nathan, 2004)

Strategy: Subtract the wrong answers from 40 to get the number right, then divide by 40; or find the percent wrong and take it away from 100%.

Traps

The wrong answers, classified

How the questions are analyzed, and the research behind it

Worked solution, step by step

Formulas used

Percent of a total
percent=partwhole×100\text{percent} = \frac{\text{part}}{\text{whole}} \times 100
The part is the number of questions you are asking about. The whole is the total number of questions on the test. Dividing gives the fraction of the test. Multiplying by 100 turns that fraction into a percent, a number out of 100.
  1. Sort out the question

    The test has 40 questions. Lemont answered 6 of them incorrectly. The question asks for the percent he answered correctly. Notice the switch. You are told the wrong answers, but you need the right ones.

  2. Count the correct answers

    Each question was either right or wrong. So take the wrong ones away from all 40.

    40−6=3440 - 6 = 34

    Lemont answered 34 questions correctly.

  3. Write 34 out of 40 as a percent

    Use the percent formula. The part is 34 questions, and the whole is 40 questions.

    percent=partwhole×100\text{percent} = \frac{\text{part}}{\text{whole}} \times 100

    percent=3440×100=85100×100=85\text{percent} = \frac{34}{40} \times 100 = \frac{85}{100} \times 100 = 85

    To get 85 out of 100, divide the top and bottom by 2, then multiply both by 5. Lemont got 85% right.

    Watch out: 640\frac{6}{40} is 15%. That is the percent he got wrong, choice D. And 34 is a number of questions, not a percent, so 34%, choice C, stops too soon.

    So the answer is A, 85%.

Check your answer

Right answers and wrong answers together make the whole test, 100%. He got 6 out of 40 wrong, which is 15%. Then 100−15=85100 - 15 = 85, so he got 85% right. Both ways give the same answer.

The original DOE question

Question 81 as printed on page 101 of the DOE handbook.
As printed in the DOE’s Specialized High Schools Student Handbook 2019–2020, page 101, question 81. Open page 101 of the handbook (PDF)