CELL PHONE SALES BY COLOR

2020 Handbook

2020 Test A Math · Question 36 of 57

Question

CELL PHONE SALES BY COLOR

Color Percent of Cell Phones Sold
White 8k8k
Black 30
Blue 30−2k30 - 2k
Red k+5k + 5
Total 100

The table above shows cell phone sales by color. What percent of the cell phones sold were blue?

  • A18%
  • B20%
  • C22%
  • D28%
Show the answer

Correct answer: B

First, use the information given in the table and properties of equations to determine the value of k.

8k+30+30−2k+k+5=1008k + 30 + 30 - 2k + k + 5 = 100

8k−2k+k+30+30+5=1008k - 2k + k + 30 + 30 + 5 = 100

7k+65=1007k + 65 = 100

7k+(65−65)=100−657k + (65 - 65) = 100 - 65

7k=357k = 35

k=5k = 5

Then determine the percentage of cell phones sold that were blue by finding the value of the expression 30−2k30 - 2k (given in the table) when k=5k = 5.

30−2k=30−2(5)=30−10=2030 - 2k = 30 - 2(5) = 30 - 10 = 20

The percentage of cell phones sold that were blue is 20%.

Question analysis

This algebra question gives cell phone sales by color in a table, with three of the percents written in terms of k: 8k for white, 30 − 2k for blue and k + 5 for red, while black is 30 and the total is 100. Students build an equation, find k, and use it to work out the blue percent, taking care with the negative term.

NYS standards
  • 7.EE.4a two-step equations
  • 7.EE.1 linear expressions with rational coefficients
Grade level
Grade 7 content, by NYS standard
Compared with grade 7
At grade 7 Grade 7 classwork usually supplies the equation. Here students must notice that the four color entries make up the whole, write and simplify a sum with a negative term, solve it, and evaluate one expression: familiar steps, a little longer than usual.
Estimated difficulty
Moderate: several steps, or a close reading with one strong distractor.
Solution
4 steps
Reading level
Question and choices: about grade 3, 36 words.
Students, last 30 days
Not enough answers yet to show (it takes 10).
Why it is hard, traps and wrong answers (shows the answer)

Why it is hard

Once the Total row becomes an equation the algebra is short, so the question mostly tests whether students see that step. Finding k is a halfway point but not a listed choice, which removes the usual early-stop trap. Students who cannot build the equation are left with the blue entry itself, and reading 2k as 2 gives the only wrong answer with a real route; the other two sit two points either side of the key and match no common slip.

  1. Many steps moderate Working it out

    Four moves in a row: add the four color entries, set the sum equal to the Total row's 100, solve 7k + 65 = 100 for k, then put k into the blue entry. (Daniel & Embretson, 2010; Enright, Morley & Sheehan, 2002)

  2. Reading a figure, table or graph minor Understanding the question

    No equation is printed; it comes from seeing that the table's four percent entries, three of them written in k, must add up to the Total of 100. (Lesh, Post & Behr, 1987; Kirsch & Mosenthal, 1990)

  3. Error-prone arithmetic minor Working it out

    Collecting like terms means keeping the blue row's negative term, 8k − 2k + k = 7k, and gathering the constants 30, 30 and 5 into 65. (Brown & Burton, 1978; Junker & Sijtsma, 2001)

Strategy: Since the color percents make up the whole, set the sum of the four entries equal to 100, gather the k terms and the constants, solve for k, and evaluate the blue entry.

Traps

  • Numbers taken from the question: Combines the numbers in the question without a model of the situation, or is simply a number that appears in the question.

The wrong answers, classified

How the questions are analyzed, and the research behind it

Worked solution, step by step

Formulas used

Combining like terms
ak+bk=(a+b)kak + bk = (a + b)k
k is the unknown number. a and b are the numbers multiplied by k, called coefficients. Terms with the same letter are like terms. You may add their coefficients, since a groups of k plus b groups of k make a + b groups of k.
Keeping an equation balanced
if a=b, then a−c=b−c and a÷c=b÷c\text{if } a = b \text{, then } a - c = b - c \text{ and } a \div c = b \div c
a and b stand for the two sides of an equation. c is any number, but not 0 when you divide. An equation works like a scale in balance. If you do the same thing to both sides, it stays balanced. Use this to get k by itself.
  1. Sort out the table

    The table gives the percent of phones sold in each color. Three of the entries use k, a letter that stands for an unknown number. 8k8k means 8 times k.

    You need the percent that were blue, 30−2k30 - 2k. To find it, you first need k.

  2. Write an equation for the total

    Every phone sold was one of the four colors. So the four percents must add up to the whole, 100. The Total row says so.

    8k+30+(30−2k)+(k+5)=1008k + 30 + (30 - 2k) + (k + 5) = 100

  3. Combine like terms

    Group the k terms together and the plain numbers together. A k on its own means 1k.

    ak+bk=(a+b)kak + bk = (a + b)k

    8k−2k+k=(8−2+1)k=7k8k - 2k + k = (8 - 2 + 1)k = 7k

    30+30+5=6530 + 30 + 5 = 65

    Now the equation is 7k+65=1007k + 65 = 100. Watch out: the blue row takes away 2k. Keep its minus sign, or the k terms come out wrong.

  4. Solve for k

    Subtract 65 from both sides. Then divide both sides by 7.

    if a=b, then a−c=b−c and a÷c=b÷c\text{if } a = b \text{, then } a - c = b - c \text{ and } a \div c = b \div c

    7k+65−65=100−657k + 65 - 65 = 100 - 65

    7k=357k = 35

    k=35÷7=5k = 35 \div 7 = 5

    So k is 5. That is not the answer yet. You still need the blue row.

  5. Find the blue percent

    Put 5 in place of k in the blue row.

    30−2k=30−2×5=30−10=2030 - 2k = 30 - 2 \times 5 = 30 - 10 = 20

    So 20% of the phones sold were blue. Watch out: 2k means 2 times k, not just 2. Reading 30−2k30 - 2k as 30−230 - 2 gives 28%, choice D.

    So the answer is B, 20%.

Check your answer

Put k = 5 into every row. White: 8×5=408 \times 5 = 40. Black: 30. Blue: 20. Red: 5+5=105 + 5 = 10. Now add them: 40+30+20+10=10040 + 30 + 20 + 10 = 100. The total matches the table, so k = 5 and 20% are right.

The original DOE question

Question 93 as printed on page 92 of the DOE handbook.
As printed in the DOE’s NYC Guide to the Specialized High Schools Admissions Test (SHSAT) for 2021 Admissions, page 92, question 93. Open page 92 of the handbook (PDF)