12.96 ÷ 0.08

2022 Handbook

2022 Test A Math · Question 24 of 57

Question

12.96÷0.08=12.96 \div 0.08 =

  • A1.62
  • B16.2
  • C162
  • D1,620
Show the answer

Correct answer: C

Since the greatest number of decimal places is 2 (hundredths), multiply both terms by 100, and then divide:

12.96(100)÷0.08(100)=12.96(100) \div 0.08(100) =

1,296÷8=1{,}296 \div 8 =

162162

Question analysis

This question asks students to divide 12.96 by 0.08, a decimal division with no story around it. It tests dividing multi-digit decimals with the standard algorithm. The choices differ only in where the decimal point falls, so moving the point the same number of places in both numbers is the whole challenge.

NYS standards
  • 6.NS.3 multi-digit decimal operations
Grade level
Grade 6 content, by NYS standard
Compared with grade 7
Below grade 7 Dividing multi-digit decimals is grade 6 fluency that grade 7 work builds on rather than teaches. The division comes out exactly, so the real demand is placing the decimal point correctly, a single routine skill.
Estimated difficulty
Straightforward: two steps or one careful reading.
What makes it hard
Solution
2 steps
Reading level
Question and choices: about grade 16+, 1 words.
Students, last 30 days
Not enough answers yet to show (it takes 10).
Why it is hard, traps and wrong answers (shows the answer)

Why it is hard

Every choice uses the digits 1, 6 and 2, so the question tests only where the decimal point goes. Dividing by a number less than one gives a result larger than 12.96, which feels wrong to students who expect division to shrink a number. Estimating first, 12.96 ÷ 0.08 is about 13 × 12.5, puts the result in the low hundreds and rules out the other three at once.

  1. Error-prone arithmetic moderate Working it out

    The divisor 0.08 has two decimal places, so both numbers must be multiplied by 100, turning the problem into 1,296 ÷ 8, and the quotient comes out larger than 12.96. (Brown & Burton, 1978; Junker & Sijtsma, 2001)

Strategy: Multiply the dividend and the divisor by the same power of 10 so that the divisor becomes a whole number, then carry out the long division.

Traps

  • An arithmetic slip: The right method with a plausible arithmetic error: a digit, a place value or a times-table fact.

The wrong answers, classified

How the questions are analyzed, and the research behind it

Worked solution, step by step

Formulas used

Dividing by a decimal
a÷b=(a×100)÷(b×100)a \div b = (a \times 100) \div (b \times 100)
a is the number being divided. b is the divisor, the number you divide by. Multiplying both by the same number, like 100, does not change the answer. Use 100 when the divisor has two decimal places, so it becomes a whole number.
  1. Sort out the question

    You need 12.96÷0.0812.96 \div 0.08. The divisor, the number you divide by, is 0.08. It has two decimal places. Dividing by a decimal is hard, so make the divisor a whole number first. All four choices use the digits 1, 6 and 2. So the real question is where the decimal point goes.

  2. Make the divisor a whole number

    Multiply both numbers by 100. This moves each decimal point two places to the right.

    12.96÷0.08=(12.96×100)÷(0.08×100)12.96 \div 0.08 = (12.96 \times 100) \div (0.08 \times 100)

    =1,296÷8= 1{,}296 \div 8

    The new problem has the same answer. Watch out: move both points the same number of places. Moving the point three places in 12.96 but two in 0.08 gives 1,620, choice D.

  3. Divide by 8

    Split 1,296 into parts that 8 divides easily.

    1,200÷8=15096÷8=121{,}200 \div 8 = 150 \qquad 96 \div 8 = 12

    1,296÷8=150+12=1621{,}296 \div 8 = 150 + 12 = 162

    Watch out: ignoring the point in 0.08 means dividing 12.96 by 8. That gives 1.62, choice A. Moving the point only one place gives 16.2, choice B. So the answer is C, 162.

Check your answer

Multiply back: 162×0.08=12.96162 \times 0.08 = 12.96. That matches. Also, 0.08 is less than 1. Dividing by a number less than 1 makes the answer bigger. And 1,620×0.08=129.61{,}620 \times 0.08 = 129.6, which is far too big.

The original DOE question

Question 81 as printed on page 85 of the DOE handbook.
As printed in the DOE’s NYC Guide to the Specialized High Schools Admissions Test (SHSAT) for 2023 Admissions, page 85, question 81. Open page 85 of the handbook (PDF)