Q50: Which number line below shows

October 15, 2026

2018 Test B Math · Question 50 of 57

$\textup{Which number line below shows the solution set for}\\ 2x-2\leq y\leq 4x+10 \textup{ when} \; y=1?$

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Correct answer: C

Separate the compound inequality into two pieces:

$2x-2leq y$ and $yleq4x+10$

Substitute $y=1$ into each inequality and solve for $x$ :

$2x-2leq1$

$2xleq3$

$xleqfrac{3}{2}$

$1leq4x-10$

$-9leq4x$

$-frac{9}{4}leq x$

The solution is the number line that shows that $x$ is greater than or equal to $-2frac{1}{4}$ and less than or equal to $1frac{1}{2}$ .